хВРі. IN OUT + VCC 15.0V U1 R1 11.25ΚΩ C2 2nF - V1 10VPK 1 kHz 2 TH VDC5 JUA741 CD --15.0V 00 4 R3 10kg w R2 10KΩ (1)

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

хВРі. IN OUT + VCC 15.0V U1 R1 11.25ΚΩ C2 2nF - V1 10VPK 1 kHz 2 TH VDC5 JUA741 CD --15.0V 00 4 R3 10kg w R2 10KΩ (1)

Post by answerhappygod »

 1
1 (76.07 KiB) Viewed 18 times
 2
2 (111.58 KiB) Viewed 18 times
хВРі. IN OUT + VCC 15.0V U1 R1 11.25ΚΩ C2 2nF - V1 10VPK 1 kHz 2 TH VDC5 JUA741 CD --15.0V 00 4 R3 10kg w R2 10KΩ
(1) Connect the circuit according to the circuit diagram and connect Ui to the circuit. Ui is the 10Hz, 1V peak-to-peak sine signal output by the signal generator. (2) Measure the effective value of Uo with an oscilloscope, and fill this value into the following table. This voltage is the effective value Ubw of the output voltage in the passband. (3) Calculate the Ubw value of 0.707 times and fill in the form. When the input signal is close to the cutoff frequency, the output voltage will continue to drop until the effective value is equal to 0.707 times Ubw, and record the cutoff frequency fp. (4) After finding the cut-off frequency, measure the value of Uo, called Ueb at 10 times fp frequency, and fill in the form f (Hz) 10 Fp 10 * fp U. (V) Ubpass Ubstop 0.707 * Ubw
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply