***PYTHON CODING QUESTION*** So this is the question: This is my code: def vowel_consonant_ratio(sentence): """counts th
Posted: Fri Apr 29, 2022 6:40 am
***PYTHON CODING QUESTION***
So this is the question:
This is my code:
def vowel_consonant_ratio(sentence):
"""counts the number of vowels and constantants, returns
ratio"""
num_vow = 0
num_con = 0
for i in sentence:
if(i=='A' or i=='E' or i=='I' or i=='O' or i=='U' or i=='a' or
i=='e' or i=='i' or i=='o' or i=='u'):
num_vow = num_vow + 1
elif((i >='A' and i <='Z' ) or (i >='a' and i
<='z')):
num_con = num_con + 1
print("Number of vowels:", num_vow)
print("Number of consonants:", num_con)
if(num_con==0):
return 0.0;
else:
t=float(num_vow/num_con)
return round(t,4)
And these are the errors I got:
Could someone offer me a new way of doing this question, or help
me debug?
Write a function vowel_consonant_ratio(sentence) that takes an input parameter sentence (type string) and: • prints the number of vowels in the sentence, • prints the number of consonants in the sentence, and • returns the ratio of vowels to consonants as a float, rounded to 4 decimal places. The formatting for the outputs can be seen in the test cases. Cases where your function cannot perform the ratio calculation should return 0.0 NB: this one's not really a part of the typical NLP processing pipeline, but it's a fun exercise For example: Test Result sentence = "vowels and consonants" Number of vowels: 6 print(vowel_consonant_ratio(sentence)) Number of consonants: 13 0.4615 sentence = "what about this?" Number of vowels: 5 print(vowel_consonant_ratio(sentence)) Number of consonants: 8 0.625 sentence = "hooo0000000!" Number of vowels: 10 print(vowel_consonant_ratio(sentence)) Number of consonants: 1 10.0
Precheck only Precheck failed with the following unexpected output. ************* Module source source.py:14:8: W0381: Unnecessary semicolon (unnecessary-semicolon) source.py:7:11: R0916: Too many boolean expressions in if statement (10/5) (too-many-boolean-expressions source.py:7:11: R1714: Consider merging these comparisons with "in" to "i in ('A', 'E', 'I', 'o', 'u', source.py:9:14: R1716: Simplify chained comparison between the operands (chained-comparison) source.py: 9:48: R1716: Simplify chained comparison between the operands (chained-comparison) source.py: 13:4: R1705: Unnecessary "else" after "return" (no-else-return) ***Error*** Sorry, but your code doesn't pass the pylint style checks.
So this is the question:
- Python Coding Question So This Is The Question This Is My Code Def Vowel Consonant Ratio Sentence Counts Th 1 (29.99 KiB) Viewed 57 times
def vowel_consonant_ratio(sentence):
"""counts the number of vowels and constantants, returns
ratio"""
num_vow = 0
num_con = 0
for i in sentence:
if(i=='A' or i=='E' or i=='I' or i=='O' or i=='U' or i=='a' or
i=='e' or i=='i' or i=='o' or i=='u'):
num_vow = num_vow + 1
elif((i >='A' and i <='Z' ) or (i >='a' and i
<='z')):
num_con = num_con + 1
print("Number of vowels:", num_vow)
print("Number of consonants:", num_con)
if(num_con==0):
return 0.0;
else:
t=float(num_vow/num_con)
return round(t,4)
And these are the errors I got:
- Python Coding Question So This Is The Question This Is My Code Def Vowel Consonant Ratio Sentence Counts Th 2 (20.79 KiB) Viewed 57 times
me debug?
Write a function vowel_consonant_ratio(sentence) that takes an input parameter sentence (type string) and: • prints the number of vowels in the sentence, • prints the number of consonants in the sentence, and • returns the ratio of vowels to consonants as a float, rounded to 4 decimal places. The formatting for the outputs can be seen in the test cases. Cases where your function cannot perform the ratio calculation should return 0.0 NB: this one's not really a part of the typical NLP processing pipeline, but it's a fun exercise For example: Test Result sentence = "vowels and consonants" Number of vowels: 6 print(vowel_consonant_ratio(sentence)) Number of consonants: 13 0.4615 sentence = "what about this?" Number of vowels: 5 print(vowel_consonant_ratio(sentence)) Number of consonants: 8 0.625 sentence = "hooo0000000!" Number of vowels: 10 print(vowel_consonant_ratio(sentence)) Number of consonants: 1 10.0
Precheck only Precheck failed with the following unexpected output. ************* Module source source.py:14:8: W0381: Unnecessary semicolon (unnecessary-semicolon) source.py:7:11: R0916: Too many boolean expressions in if statement (10/5) (too-many-boolean-expressions source.py:7:11: R1714: Consider merging these comparisons with "in" to "i in ('A', 'E', 'I', 'o', 'u', source.py:9:14: R1716: Simplify chained comparison between the operands (chained-comparison) source.py: 9:48: R1716: Simplify chained comparison between the operands (chained-comparison) source.py: 13:4: R1705: Unnecessary "else" after "return" (no-else-return) ***Error*** Sorry, but your code doesn't pass the pylint style checks.