b) A horizontal cylinder rotates as shown. A uniform horizontal air velocity (U) approaches the cylinder. What uniform a
Posted: Thu Apr 28, 2022 8:40 pm
b) A horizontal cylinder rotates as shown. A uniform horizontal air velocity (U) approaches the cylinder. What uniform air velocity (U) results in the desired lift force? Use standard air conditions. 2.0 m 5.0 m 400 RPM 3 Diameter, D = Length, L = Rotational Speed = Desired Lift Force = 2 UO CL = -0.295 ) + 1.909 Co)- 0.549 2.0 KN Lift Force The equation above is the lift coefficient, CL, as a function of the spin parameter (U/U) for a smooth rotating cylinder in Magnus effect. U, is the tangential speed of the cylinder surface and U is the uniform velocity of the approach air (Reid 1924). The reference area for this lift coefficient is the frontal cross section (the area the wind "sees"). C U?