e to plastic centroid Pud 14" zole 23 3" 22" 3 No. 14 (No. 43) 2 No.11 (No. 36) Darwin et al. Fig P9-8 For the column sh

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e to plastic centroid Pud 14" zole 23 3" 22" 3 No. 14 (No. 43) 2 No.11 (No. 36) Darwin et al. Fig P9-8 For the column sh

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E To Plastic Centroid Pud 14 Zole 23 3 22 3 No 14 No 43 2 No 11 No 36 Darwin Et Al Fig P9 8 For The Column Sh 1
E To Plastic Centroid Pud 14 Zole 23 3 22 3 No 14 No 43 2 No 11 No 36 Darwin Et Al Fig P9 8 For The Column Sh 1 (96.08 KiB) Viewed 30 times
e to plastic centroid Pud 14" zole 23 3" 22" 3 No. 14 (No. 43) 2 No.11 (No. 36) Darwin et al. Fig P9-8 For the column shown above, calculate the eccentricity of axial load corresponding to balance failure. Hint: Note that the eccentricity must have measured from the plastic centroid, thus determine the location of the plastic centroid for the given section (using EQN 9.17 of Darwin et al.). Using strain compatibility, determine the neutral axis depth corresponding to balance failure, cb. Then, determine the concrete and steel stress resultants corresponding to Ch. Calculate P, using EQN 9.7. Then calculate M, using and equation similar to EQN 2 (but not the same), by taking moments about the plastic centroid rather than about geometric center. The required eccentricity is ep=M./Pn. Note that the calculated M, and P, represent the balanced point in the interactive curve. Other points on the interaction curve can be determined by selecting values of a larger than Co (resulting in point on the compression governed region of the interaction curve), and smaller than Cp (resulting in the points on the tension governed region of the interaction curve) and calculating the corresponding Pn and mn using the plastic centroid as described above. P = 0.85f' ab +f; A-f, A, (9.7) X 0.85bh2/2 +f,A,d+f, Ad' 0.85fbh +f, A, +fA (9.17)
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