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A simple light-framed wood building is subjected to the load conditions as specifled. -R-10 AM RIDO DEAM 2x RAFTEMS COLU

Posted: Thu Apr 28, 2022 8:29 pm
by answerhappygod
A Simple Light Framed Wood Building Is Subjected To The Load Conditions As Specifled R 10 Am Rido Deam 2x Raftems Colu 1
A Simple Light Framed Wood Building Is Subjected To The Load Conditions As Specifled R 10 Am Rido Deam 2x Raftems Colu 1 (309.27 KiB) Viewed 28 times
A simple light-framed wood building is subjected to the load conditions as specifled. -R-10 AM RIDO DEAM 2x RAFTEMS COLUMN_FLOOR PBARING WALLS ELIH H CONCRETE poot No WPT 32' CAPTO STEM WALL -SARINE WALL UNTINIO CONCIPIO FONDATION por TINGS SECTION THROUGH BUILDING (Continuous foundation) COLUMN 16 BEARING WALLS. RIDGE BSAM COLUMN 2x RAFTERS 10 COLUMN SPAN SPAN 14! + 2x PT Tosts I'. FLOR DEAM CONTINUOUS CONCRETE FOUNDATION WALL FRAMING PLAN-ROOF FORTING (Interior spread footing) . + Along rafter length: • Roof pitch: 5:12 • Dead load (roofing + sheathing + celling + rafters) = 25 pst • Live load (snow) = 50 psf • Ridge beam spans 16 feet from column support to column support Please round to the nearest one-tenth (l.e., 0.1). Determine the equivalent (horizontally projected) total load on the rafters = lb/ft Determine the load per foot on the bearing wall at the bottom), including the wall weight (wall dead load = 7 psf and wall height, H = 10 ft) = ib/ft
Determine the load per foot on the bearing wall (at the bottom), including the wall weight (wall dead load = 7 psf and wall height, H = 10 ft) = Ib/ft Determine the load per foot on the ridge beam = Ib/ft Determine the load on the Interior column= | Ib Floor load conditions: • Floor dead load (flooring + subfloor + joists) = 25 psf • Live load (occupancy) = 150 psf Determine the floor joist reactions into load per foot on the continuous foundation (one side) = lb/ft Determine the floor joist reactions into load per foot on the floor beam = Ib/ft Foundation conditions: . Continuous foundation's stem wall is 8 inch thick and 2 ft tall • Footing base is 8 inch thick • Concrete density = 150 pcf • Soil bearing capacity = 1200 psf Determine the minimum theoretical width of the continuous foundation = ft (Round to the nearest tenth!) ft (Round Determine the minimum theoretical width of the interior spread footing for the critical center column = to the nearest tenth!)