Figure Q1 shows a soil profile. An oedometer test was conducted on a specimen collected from the middle of the clay laye
Posted: Thu Apr 28, 2022 3:36 pm
Figure Q1 shows a soil profile. An oedometer test was conducted
on a specimen collected from the middle of the clay layer. The
results of the oedometer test on a clay specimen are: Cc = 0.2, Cs
= 0.04, OCR = 4.5. The uniformly distributed surcharge of Δσ is
applied at the ground surface. Given: Δσ = 100 kN/m2 , H1 = 2.5 m,
H2 = 2.5 m, H3 = 3 m. Also, Sand: e = 0.64, Gs = 2.65
Clay: Gs = 2.75, w (water content) = 43 %
Where, OCR is the overconsolidation ratio, defined by the ratio
of maximum value of effective stress in the past (preconsolidation
pressure) to the present value.
→ > H ffム★ H H Sand Clay Figure Q1 a) Calculate the primary consolidation settlement. b) What would be the difference in settlement if OCR were 1.5 instead of 4.5.
on a specimen collected from the middle of the clay layer. The
results of the oedometer test on a clay specimen are: Cc = 0.2, Cs
= 0.04, OCR = 4.5. The uniformly distributed surcharge of Δσ is
applied at the ground surface. Given: Δσ = 100 kN/m2 , H1 = 2.5 m,
H2 = 2.5 m, H3 = 3 m. Also, Sand: e = 0.64, Gs = 2.65
Clay: Gs = 2.75, w (water content) = 43 %
Where, OCR is the overconsolidation ratio, defined by the ratio
of maximum value of effective stress in the past (preconsolidation
pressure) to the present value.
→ > H ffム★ H H Sand Clay Figure Q1 a) Calculate the primary consolidation settlement. b) What would be the difference in settlement if OCR were 1.5 instead of 4.5.