Answer Happy • y" + 2y' + 5y = sin x +cos 2x y' + 4y' + 5y = 35e-4x, y(0) = -3, y'(0) = 1

Page 1 of 1

y" + 2y' + 5y = sin x +cos 2x y' + 4y' + 5y = 35e-4x, y(0) = -3, y'(0) = 1

Posted: Thu Apr 28, 2022 6:34 am

by answerhappygod

: Y 2y 5y Sin X Cos 2x Y 4y 5y 35e 4x Y 0 3 Y 0 1 1 (17.36 KiB) Viewed 41 times

: Y 2y 5y Sin X Cos 2x Y 4y 5y 35e 4x Y 0 3 Y 0 1 2 (12.89 KiB) Viewed 41 times

Solve with constant coefficients
y" + 2y' + 5y = sin x +cos 2x

y' + 4y' + 5y = 35e-4x, y(0) = -3, y'(0) = 1