Page 1 of 1
1 Provide a detailed proof for the following statement: If the function g: [0, 1] →R is integral realizable, then g is L
Posted: Thu Apr 28, 2022 6:31 am
by answerhappygod
- 1 Provide A Detailed Proof For The Following Statement If The Function G 0 1 R Is Integral Realizable Then G Is L 1 (70.99 KiB) Viewed 38 times
1 Provide a detailed proof for the following statement: If the function g: [0, 1] →R is integral realizable, then g is Lipschitz. The function is integral realizable if g: [0,1] → R is continuous and differentiable on (0,1) with g'(x) bounded and continuous when it exists. The function is Lipschitz if there exists some E such that g(x) - g(y) = Elx - y for all x, y €[0,1].