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-0.6 m 2.42 The springs on the rope assembly are originally unstretched when = 0°. Determine the tension in each rope when F = 450 N. Neglect the size of the pulleys at B and D. 0.6 m k=500 N/m k=500 N/m 0.6 cos T-krek(-1) - 500 0.6 m 0.6 cos -0.6 ) - 300 - 1) (1) cos of 1 (2) Y +TEF, = 0; 2 T sin 8-450=0 Substituting Eq. (1) into (2) yields: 600 (tan 8-sin ) - 450 = 0 tan 8-sine -0.75 By trial and error: T مد X = 57.957 From Eq. (1), T= 300 F = 450 N 1 cos 57.957 - 1) - 2 = 265.4 N Ans