Sub: Architectural steel structure design. please follow this formula ( this is two crane) and solve the red box questio
Posted: Wed Apr 27, 2022 2:44 pm
Sub: Architectural steel structure design.
please follow this formula ( this is two crane)
and solve the red box question one crane.
Simply supported crane beam, span is 12 m, one crane, vertical wheel pressure Pk, max x=520 kN (characteristic value), steel design flexural strength F295 N/mm2 and shear strength fx= 170 N/mm2, partial coefficient of dead load is 1.2, partial coefficient of live load 1.4, dynamic coefficient a is 1.1, xo=365mm, a, is 0.1 Please check whether flexural strength, shear strength, vertical deflection is satisfied ? > 200 -8 x 760 40 -22 x 500 120 120 [28a 10 max Pk, max Pk, Wheel Y1 Wheel * 650 5250 650 -22 x 500 6 550 -14 x 1 600 Width of crane bridge Cross section (unit: mm)
3.7: Example of crane beam design Simply supported crane beam, span is 12m, two cranes, vertical load Pk.max=491kN (characteristic value), steel design flexural strength F=295 N/mm² and shear strength f= 170 N/mm², partial coefficient of dead load is 1.2, partial coefficient of live load 1.4, dynamic coefficient a is 1.1, xo=365mm, a is 0.1 2 200 -8 x 760 40 -22 x 500 120 120 ILIO [28a 10 P=491 KN 491 kN 71 Wheel Wheel 31 650 5 250 650 -22 x 500 6 550 -14 x 1 600 Cross section (unit: mm) Width of crane bridge 3.7: Example of crane beam design Parameter of crane beam 71 200 - 8 x 760 40 -22 x 500 120 120 [28a X0 21 С 21 21 -22 x 500 -14 x 1 600 B Moment inertial: 1x=1819843.7 cm Point A or B: resistance inertial: W = 1/82.2=21978.8 cm ni Point C: area inertial: Sy=13401 cm 3.7: Example of crane beam design Parameter of brake beam 71 200 -8 x 760 40 -22 x 500 120 120 ++ [28a Xo 11 210 2 X1 X1 -22 x 500 -14 x 1 600 Moment inertial: 1ny=362116.9 cm Point A: resistance inertial: Wnx= 1//62.2=5821.8 cm
3.7: Example of crane beam design (1) Global stability Not necessary to be considered, brake beam can be lateral brace of crane beam to avoid global buckling. (2) Strength Include flexural strength and shear strength (design value of load, two cranes, dynamic coefficient) 3.7: Example of crane beam design (2.1) Flexural strength M (design moment)is caused by vertical load P and beard by crane beam. Mx Maximum compression stress (point A): 0 = Maximum tension stress (point B) Р W nx 71 200 -8 x 760 40 -22 x 500 120 120 + Comp. [28a Xo 1 M C * -22 x 500 -14X1 600 Tens. B 3.7: Example of crane beam design (2.1) Flexural strength M, (design value) is caused by horizontal load T and beard by brake beam. My Maximum compression stress (point A): 0 = Wn ny Comp. Tens. yi 200 -8 x 760 40 -22 x 500 M, A 120 120 T [28a 10 J1 x 31 11 -22 x 500 -14 x 1 600
3.7: Example of crane beam design (2.1) Flexural strength The maximum flexural stress (compression) occurs at Point A. му M x 0= + W nx W ny How to determinate M, and M,? X 3.7: Example of crane beam design (2.1) Flexural strength Internal force M caused by two cranes Pk,max=491kN (characteristic value) T= a;P k,max =0.1x491=49.1kN (characteristic value) R-resultant force Pk,mas Pk.na P k,max 491 491491 1 1 408.5 3933 300 4 041.5 * 658.5 6 000 658.5 6 000 817.3 kN R.2x=5250P R=3x491, x=658.5 k,max-1300P, k,max 3.7: Example of crane beam design 20-21/30 (2.1) Flexural strength Internal force M, caused by two cranes Center line R-resultant force 491 R 491491 十 1 408.5 3933 300 4 041.5 658.5 6 000 658.5 6 000 817.3 kN Support reaction RX=817.3 kN Maximum moment-cross section When the centerline of the beam is at the middle of the locations of resultant force R and the nearest wheel pressure! Maximum moment occurs at the cross section corresponding to the nearest wheel pressure.
3.7: Example of crane beam design (2.1) Flexural strength Internal force M, caused by two cranes Center line R-resultant force R 491 491491 TH 中 1 408.5 3933 1 300 4 041.5 * 658.5 6 000 658.5 6 000 817.3 kN Support reaction RA=817.3 kN Maximum moment-cross section Mkmax = 871.3 x 6.658 5 kN•m - 491 x (3.933 +0.658 5 x 2) kN•m = 2 864.2 kN•m Characteristic value of moment, caused by live load Pk,max 3.7: Example of crane beam design (2.1) Flexural strength Internal force M. caused by two cranes Assume that the moment caused by self-weight is 5%Mkmax Design value Mx=1.2x5%Mkmax+1.4x1.1x Mkmax=4582.7 kN.m Internal force M, caused by two cranes Mwy = 2 864.2 kv.m x 49. 1/491 = 286.4 kN.m Design value My=1.4x1.1x Mky=441.1 kN.m M My + = 4582.7x106 441.1x106 + 284.3N/mm²<f=295N/mm² 21978.8x103 5821.8x103 Wix W ny 3.7: Example of crane beam design (2.2) Shear strength Internal force V caused by two cranes 491, 491 491 23-24/30 11 300 5 250 5 450 12 000 Location of two cranes when the crane beam achieves the maximum shear force
3.7: Example of crane beam design (2.2) Shear strength Internal force V caused by two cranes 491, 491 491 01 300 5 250 5 450 12 000 Maximum shear force-cross section Vimax = 491 kN x (5.45 + 10.7 +12)/12 = 1 151.8 kN 3.7: Example of crane beam design (2.2) Shear strength Internal force V caused by two cranes Assume that the shear force caused by self-weight is 5%Vkmax Design value V=1.2x5%V x+1.4x1.1x Vkmax=1842.9 kN Р kmax 1 200 -8 x 760 40 - 22 x 500 120 120 [28a 10 Maximum shear stress (point C): 1 -22 x 500 -14 x 1 600 3.7: Example of crane beam design (2.2) Shear strength Internal force V caused by two cranes Assume that the shear force caused by self-weight is 5%Vkmax Design value V=1.2x5%V kmax+1.4x1.1x V kmax=1842.9 kN Maximum shear stress (point C): VS. T It 1 842.9 x 10 x 13 401 x 103 N/mm² = 96.9 N/mm² <f. 1819843.7 x 109 x 14 =170N/mm2
3.7: Example of crane beam design (3) Deflection (characteristic value of load, one crane, no dynamic coefficient) Internal force M caused by one crane R-resultant force Center line P k,max 491 P k,max 491 R 4 687.5 1312.5 2 625 2062.5 6 000 1 312.5 6 000 Maximum moment-cross section Support reaction Ra=383.6 kN 3.7: Example of crane beam design (3) Deflection (characteristic value of load, one crane, no dynamic coefficient) Internal force M caused by one crane (3.1) Vertical deflection caused by vertical load P 383.6 kN x 4.687 5 m = 1 798. 1 kN•m M pmax = = M. 1 V= = 1 798.1 x 106 x 12 0002 10 x 2.06 x 10 x 1819843.7 x 104 mm 10EI, = 6.9 mm <[v] 1 = 16 mm 750 3.7: Example of crane beam design (3) Deflection (characteristic value of load, one crane, no dynamic coefficient) Internal force M caused by one crane (3.2) horizontal displacement caused by horizontal load T Mk = 1 798. 1 kN.m x 49. 1/491 179.8 kN.m U= M.,?? 179.8 x 100 x 12 0002 10EL 10 x 2.06 x 10° ~ 362 116.9 x 104 mm = 3. 47 mm < 1 = 10 mm 1 200
- Sub Architectural Steel Structure Design Please Follow This Formula This Is Two Crane And Solve The Red Box Questio 1 (101.47 KiB) Viewed 48 times
and solve the red box question one crane.
- Sub Architectural Steel Structure Design Please Follow This Formula This Is Two Crane And Solve The Red Box Questio 2 (132.58 KiB) Viewed 48 times
- Sub Architectural Steel Structure Design Please Follow This Formula This Is Two Crane And Solve The Red Box Questio 3 (128.68 KiB) Viewed 48 times
- Sub Architectural Steel Structure Design Please Follow This Formula This Is Two Crane And Solve The Red Box Questio 4 (140.58 KiB) Viewed 48 times
- Sub Architectural Steel Structure Design Please Follow This Formula This Is Two Crane And Solve The Red Box Questio 5 (145.66 KiB) Viewed 48 times
- Sub Architectural Steel Structure Design Please Follow This Formula This Is Two Crane And Solve The Red Box Questio 6 (126.19 KiB) Viewed 48 times
- Sub Architectural Steel Structure Design Please Follow This Formula This Is Two Crane And Solve The Red Box Questio 7 (149.13 KiB) Viewed 48 times
3.7: Example of crane beam design Simply supported crane beam, span is 12m, two cranes, vertical load Pk.max=491kN (characteristic value), steel design flexural strength F=295 N/mm² and shear strength f= 170 N/mm², partial coefficient of dead load is 1.2, partial coefficient of live load 1.4, dynamic coefficient a is 1.1, xo=365mm, a is 0.1 2 200 -8 x 760 40 -22 x 500 120 120 ILIO [28a 10 P=491 KN 491 kN 71 Wheel Wheel 31 650 5 250 650 -22 x 500 6 550 -14 x 1 600 Cross section (unit: mm) Width of crane bridge 3.7: Example of crane beam design Parameter of crane beam 71 200 - 8 x 760 40 -22 x 500 120 120 [28a X0 21 С 21 21 -22 x 500 -14 x 1 600 B Moment inertial: 1x=1819843.7 cm Point A or B: resistance inertial: W = 1/82.2=21978.8 cm ni Point C: area inertial: Sy=13401 cm 3.7: Example of crane beam design Parameter of brake beam 71 200 -8 x 760 40 -22 x 500 120 120 ++ [28a Xo 11 210 2 X1 X1 -22 x 500 -14 x 1 600 Moment inertial: 1ny=362116.9 cm Point A: resistance inertial: Wnx= 1//62.2=5821.8 cm
3.7: Example of crane beam design (1) Global stability Not necessary to be considered, brake beam can be lateral brace of crane beam to avoid global buckling. (2) Strength Include flexural strength and shear strength (design value of load, two cranes, dynamic coefficient) 3.7: Example of crane beam design (2.1) Flexural strength M (design moment)is caused by vertical load P and beard by crane beam. Mx Maximum compression stress (point A): 0 = Maximum tension stress (point B) Р W nx 71 200 -8 x 760 40 -22 x 500 120 120 + Comp. [28a Xo 1 M C * -22 x 500 -14X1 600 Tens. B 3.7: Example of crane beam design (2.1) Flexural strength M, (design value) is caused by horizontal load T and beard by brake beam. My Maximum compression stress (point A): 0 = Wn ny Comp. Tens. yi 200 -8 x 760 40 -22 x 500 M, A 120 120 T [28a 10 J1 x 31 11 -22 x 500 -14 x 1 600
3.7: Example of crane beam design (2.1) Flexural strength The maximum flexural stress (compression) occurs at Point A. му M x 0= + W nx W ny How to determinate M, and M,? X 3.7: Example of crane beam design (2.1) Flexural strength Internal force M caused by two cranes Pk,max=491kN (characteristic value) T= a;P k,max =0.1x491=49.1kN (characteristic value) R-resultant force Pk,mas Pk.na P k,max 491 491491 1 1 408.5 3933 300 4 041.5 * 658.5 6 000 658.5 6 000 817.3 kN R.2x=5250P R=3x491, x=658.5 k,max-1300P, k,max 3.7: Example of crane beam design 20-21/30 (2.1) Flexural strength Internal force M, caused by two cranes Center line R-resultant force 491 R 491491 十 1 408.5 3933 300 4 041.5 658.5 6 000 658.5 6 000 817.3 kN Support reaction RX=817.3 kN Maximum moment-cross section When the centerline of the beam is at the middle of the locations of resultant force R and the nearest wheel pressure! Maximum moment occurs at the cross section corresponding to the nearest wheel pressure.
3.7: Example of crane beam design (2.1) Flexural strength Internal force M, caused by two cranes Center line R-resultant force R 491 491491 TH 中 1 408.5 3933 1 300 4 041.5 * 658.5 6 000 658.5 6 000 817.3 kN Support reaction RA=817.3 kN Maximum moment-cross section Mkmax = 871.3 x 6.658 5 kN•m - 491 x (3.933 +0.658 5 x 2) kN•m = 2 864.2 kN•m Characteristic value of moment, caused by live load Pk,max 3.7: Example of crane beam design (2.1) Flexural strength Internal force M. caused by two cranes Assume that the moment caused by self-weight is 5%Mkmax Design value Mx=1.2x5%Mkmax+1.4x1.1x Mkmax=4582.7 kN.m Internal force M, caused by two cranes Mwy = 2 864.2 kv.m x 49. 1/491 = 286.4 kN.m Design value My=1.4x1.1x Mky=441.1 kN.m M My + = 4582.7x106 441.1x106 + 284.3N/mm²<f=295N/mm² 21978.8x103 5821.8x103 Wix W ny 3.7: Example of crane beam design (2.2) Shear strength Internal force V caused by two cranes 491, 491 491 23-24/30 11 300 5 250 5 450 12 000 Location of two cranes when the crane beam achieves the maximum shear force
3.7: Example of crane beam design (2.2) Shear strength Internal force V caused by two cranes 491, 491 491 01 300 5 250 5 450 12 000 Maximum shear force-cross section Vimax = 491 kN x (5.45 + 10.7 +12)/12 = 1 151.8 kN 3.7: Example of crane beam design (2.2) Shear strength Internal force V caused by two cranes Assume that the shear force caused by self-weight is 5%Vkmax Design value V=1.2x5%V x+1.4x1.1x Vkmax=1842.9 kN Р kmax 1 200 -8 x 760 40 - 22 x 500 120 120 [28a 10 Maximum shear stress (point C): 1 -22 x 500 -14 x 1 600 3.7: Example of crane beam design (2.2) Shear strength Internal force V caused by two cranes Assume that the shear force caused by self-weight is 5%Vkmax Design value V=1.2x5%V kmax+1.4x1.1x V kmax=1842.9 kN Maximum shear stress (point C): VS. T It 1 842.9 x 10 x 13 401 x 103 N/mm² = 96.9 N/mm² <f. 1819843.7 x 109 x 14 =170N/mm2
3.7: Example of crane beam design (3) Deflection (characteristic value of load, one crane, no dynamic coefficient) Internal force M caused by one crane R-resultant force Center line P k,max 491 P k,max 491 R 4 687.5 1312.5 2 625 2062.5 6 000 1 312.5 6 000 Maximum moment-cross section Support reaction Ra=383.6 kN 3.7: Example of crane beam design (3) Deflection (characteristic value of load, one crane, no dynamic coefficient) Internal force M caused by one crane (3.1) Vertical deflection caused by vertical load P 383.6 kN x 4.687 5 m = 1 798. 1 kN•m M pmax = = M. 1 V= = 1 798.1 x 106 x 12 0002 10 x 2.06 x 10 x 1819843.7 x 104 mm 10EI, = 6.9 mm <[v] 1 = 16 mm 750 3.7: Example of crane beam design (3) Deflection (characteristic value of load, one crane, no dynamic coefficient) Internal force M caused by one crane (3.2) horizontal displacement caused by horizontal load T Mk = 1 798. 1 kN.m x 49. 1/491 179.8 kN.m U= M.,?? 179.8 x 100 x 12 0002 10EL 10 x 2.06 x 10° ~ 362 116.9 x 104 mm = 3. 47 mm < 1 = 10 mm 1 200