This Question Has Several Parts That Must Be Completed Sequentially If You Skip A Part Of The Question You Will Not Re 1 (308.58 KiB) Viewed 43 times
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not recel any points for the skipped part, and you will not be able to come back to the skipped part. A light string can support a stationary hanging load of 23.9 kg before breaking. An object of mass m=2.96 kg attached to the string rotates on a frictionless, horizontal table in a circle of radius r=0.788 m, and the other end of the string is held fixed as in the figure below. What range of speeds can the object have before the string breaks?
The string will break if the tension T exceeds the following value. Tmax =mg =N N As the 2.96-kg mass rotates in a horizontal circle, the tension provides the centripetal acceleration, which is specified by ac=v2/r. From Newton's second law, we have ∑F=ma and since ac=rv2, We have the following for the tension in the string. T=rmv2
Solving for the speed, we have the following inequality relating the speed to the maximum load that the string can support before breaking. v2=mrT = kg(m)T ≤kg(m)Tmax Substituting the given value for this maximum load, we find v2≤ Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. m2/s2. Taking the square root, we find that the range of speeds is given by the following inequality. 0≤v≤m/s
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