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Show {(x, y, z)| (x2 + 2y?)2 + x2 + 2y? > 6, z E R} is an open set.
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Show {(x, y, z)| (x2 + 2y?)2 + x2 + 2y? > 6, z E R} is an open set.
Posted:
Tue Sep 07, 2021 7:58 am
by
answerhappygod
Show X Y Z X2 2y 2 X2 2y 6 Z E R Is An Open Set 1 (1.89 KiB) Viewed 76 times
Show {(x, y, z)| (x2 + 2y?)2 + x2 + 2y? > 6, z E R} is an open set.