Approximate the zero p of f(x) = 6000 - 1000 (1+x)/x [(1+x)^5 -1] using the secant method with accuracy 10^-12 and initi
Posted: Tue Sep 07, 2021 7:58 am
Approximate the zero p of
f(x) = 6000 - 1000 (1+x)/x [(1+x)^5 -1]
using the secant method with accuracy 10^-12 and initial guesses p0=0.3 and p1=-0.3. How many iterations n did you use?
f(x) = 6000 - 1000 (1+x)/x [(1+x)^5 -1]
using the secant method with accuracy 10^-12 and initial guesses p0=0.3 and p1=-0.3. How many iterations n did you use?