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= (a) A light, rigid rod of length l = 1.00 m joins two particles, with masses m1 4.00 kg and m2 = 3.00 kg, at its ends.
Posted: Wed Apr 27, 2022 7:55 am
by answerhappygod
- A A Light Rigid Rod Of Length L 1 00 M Joins Two Particles With Masses M1 4 00 Kg And M2 3 00 Kg At Its Ends 1 (114.67 KiB) Viewed 41 times
= (a) A light, rigid rod of length l = 1.00 m joins two particles, with masses m1 4.00 kg and m2 = 3.00 kg, at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod (see figure below). Determine the angular momentum of the system about the origin when the speed of each particle is 6.80 m/s. (Enter the magnitude to at least two decimal places in kg · m2/s.) . m2 X mi 23.8 kg · m2/s . magnitude direction +z . (b) What If? What would be the new angular momentum of the system (in kg · m2/s) if each of the masses were instead a solid sphere 11.5 cm in diameter? (Round your answer to at least two decimal places.) x kg. m2/s 24.455