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(a) A light, rigid rod of length l = 1.00 m joins two particles, with masses my = 4.00 kg and m2 = 3.00 kg, at its ends.

Posted: Wed Apr 27, 2022 7:47 am
by answerhappygod
A A Light Rigid Rod Of Length L 1 00 M Joins Two Particles With Masses My 4 00 Kg And M2 3 00 Kg At Its Ends 1
A A Light Rigid Rod Of Length L 1 00 M Joins Two Particles With Masses My 4 00 Kg And M2 3 00 Kg At Its Ends 1 (82 KiB) Viewed 39 times
(a) A light, rigid rod of length l = 1.00 m joins two particles, with masses my = 4.00 kg and m2 = 3.00 kg, at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod (see figure below). Determine the angular momentum of the system about the origin when the speed of each particle is 4.00 m/s. (Enter the magnitude to at least two decimal places in kg .m2/s.) my mi magnitude 14 kg .m2/s direction +z (b) What If? What would be the new angular momentum of the system (in kg . m2/s) if each of the masses were instead a solid sphere 11.0 cm in diameter? (Round your answer to at least two decimal places.) kg ·m2/5