1. La esfera de 0.300 kg se desliza desde reposo en una superficie libre de fricción y golpea un bloque de masa de 3.00
Posted: Wed Apr 27, 2022 7:40 am
1. La esfera de 0.300 kg se desliza desde reposo en una superficie libre de fricción y golpea un bloque de masa de 3.00 kg que se encuentra también en reposo. La colisión es elástica. a. Utilizando la conservación de la energia mecánica, desarrolle y halle la velocidad de la esfera en el instante que choca con el bloque. La altura es 10 m. De no desarrollar antes la expresión antes obtendrá en el problema. (mv2 - mv} + mgh – mgho = 0) 5 puntos
The 0.300-kg sphere slides from rest on a frictionless surface and strikes a block of mass 3.00 kg that is also at rest. The collision is elastic. A. Using conservation of mechanical energy, expand and find the speed of the sphere at the instant it collides with the block. The height is 10m. If the expression is not developed before you will get 0 in the problem. ((1/2)mv2 - (1/2mv2, + mgh - mgho = 0) the correct problem is in the picture in Spanish B. With conservation of momentum, use the equations for the velocities of both bodies after an elastic collision. (You don't have to work out the equations, they are found in the module and in the textbook).
The 0.300-kg sphere slides from rest on a frictionless surface and strikes a block of mass 3.00 kg that is also at rest. The collision is elastic. A. Using conservation of mechanical energy, expand and find the speed of the sphere at the instant it collides with the block. The height is 10m. If the expression is not developed before you will get 0 in the problem. ((1/2)mv2 - (1/2mv2, + mgh - mgho = 0) the correct problem is in the picture in Spanish B. With conservation of momentum, use the equations for the velocities of both bodies after an elastic collision. (You don't have to work out the equations, they are found in the module and in the textbook).