Answer Happy

---------------------------THIS IS THE 4rd time i'm
posting this question: and nobody
have calculated right. I have the answers to
this exercise from my teacher, but I dont get the same results and
I use the same equation they have given in the exercise: Please
tell me how they get the values for initial rate?
A PRACTICAL EXAMPLE. Maltase is an enzyme that cleaves the discaaharide maltose into two glucose molecules. In a series of experiments 1.3 nM maltase is added to solutions with different maltose concentrations (0, 5, 10, 15 .....UM). After 10 sec the reaction is stopped and the concentration of product (glucose) is measured. Subsequently the inhibitory effect of glucose (product inhibition) is investigated in trials with glucose added to the buffer Results: First step: find the rate v=A[PI/At [S] [product] [S] [product] Rate HOW HAVE THEY FOUND THESE VALUES FOR INITIAL RATES!!! THIS IS THE RESULTS FOR INITIAL RATES, I JUST WANT TO KNOW HOW THEY HAVE FOUND THEM!!! UM UM UM 0 0.036959 5 1.769447 10 3.054488 15 4.008363 20 4.837002 25 5.467749 30 5.965624 35 6.386844 40 6.809087 UM UM/sec 0 0.036959 0.001848 5 1.769447 0.088472 10 3.054488 0.152724 15 4.008363 0.200418 20 4.837002 0.24185 25 5.467749 0.273387 30 5.965624 0.298281 35 6.386844 0.319342 40 6.809087 0.340454 45 7.057573 0.352879 50 7.33983 0.366992 A