Please help me as I put both 91.29 g and 91.3 grams for the mass of urea but it says it's incorrect. I greatly appreciat
Posted: Wed Apr 27, 2022 6:12 am
Please help me as I put both 91.29 g and 91.3 grams for the mass of urea but it says it's incorrect. I greatly appreciate your help! Thank you. I will give likes.
Enter your answer in the provided box. Calculate the mass of urea that should be dissolved in 201 g of water at 35°C to produce a solution with a vapor pressure of 37.3 mmHg. (At 35°C, pº = 42.2 mmHg.) water
© We have to Calculate mass ob 11a As we know Psol - x solvent X Solvent where psol Vapouse sowtion ob Pressure = 37.3 mm Hg Psolvent - watery of 42.2 mm mming Vapowr pressure Mole fraction of 임 X Solvent solvent ? solvent Number of moles of solvent Total number of moles in sowtion moles of solvent CH₂O) 201 Given mass molar mass 11.17 mol 18 and Let moles ol tea be n then X solvent 11.17 n+11.17 X solvent Psol 37.3 Psolvent 42.2 11.17 37.3 1.17 = 0.88 (+11.17) n+11.17 42.2 n = 1.52 mol Now, mass of wrea moles of wrea X molar mass mass of wea 1.52 X 60.06 = 91.29 g Therefore mass of wrea is 91.29 ot q
- Please Help Me As I Put Both 91 29 G And 91 3 Grams For The Mass Of Urea But It Says It S Incorrect I Greatly Appreciat 1 (24.1 KiB) Viewed 31 times
- Please Help Me As I Put Both 91 29 G And 91 3 Grams For The Mass Of Urea But It Says It S Incorrect I Greatly Appreciat 2 (85.27 KiB) Viewed 31 times
© We have to Calculate mass ob 11a As we know Psol - x solvent X Solvent where psol Vapouse sowtion ob Pressure = 37.3 mm Hg Psolvent - watery of 42.2 mm mming Vapowr pressure Mole fraction of 임 X Solvent solvent ? solvent Number of moles of solvent Total number of moles in sowtion moles of solvent CH₂O) 201 Given mass molar mass 11.17 mol 18 and Let moles ol tea be n then X solvent 11.17 n+11.17 X solvent Psol 37.3 Psolvent 42.2 11.17 37.3 1.17 = 0.88 (+11.17) n+11.17 42.2 n = 1.52 mol Now, mass of wrea moles of wrea X molar mass mass of wea 1.52 X 60.06 = 91.29 g Therefore mass of wrea is 91.29 ot q