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I've already completed the graph, I just need help with the last two questions, "Find the value of G and plot the theore

Posted: Mon Jul 18, 2022 6:33 am
by answerhappygod
I've already completed the graph, I just need help with the lasttwo questions, "Find the value of G and plot the theoretical line".I've attached all the information you should need. My data tableand the best fit line equation.
I Ve Already Completed The Graph I Just Need Help With The Last Two Questions Find The Value Of G And Plot The Theore 1
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I Ve Already Completed The Graph I Just Need Help With The Last Two Questions Find The Value Of G And Plot The Theore 2
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I Ve Already Completed The Graph I Just Need Help With The Last Two Questions Find The Value Of G And Plot The Theore 3
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Determine the acceleration of gravity • Plot the acceleration down the track vs. sin Title: • Find the value of "g" using a best-fit line. Show work here. . On this last graph plot the theoretical line using the accepted value for ā€œgā€. g=9.81 m/s. Note: The y-intercept of the theoretical line is zero.

y(x) =- 1.072 The acceleration is -1.072 m/s2. Incline angle (deg) Average acceleration (m/s Cart accelerating down incline Acceleration sin(0) trial 1 trial 2 trial 3 (m/s) (m/s2) (m/s) .1219 0.9900 0.9820 0.9950 .1045 0.8130 0.8320 0.8380 .0871 0.6020 0.6020 0.6010 .0697 0.5100 0.5090 0.5110 0.989 0.828 0.602 0.51 .0523 0.3370 0.3370 0.3350 0.3363 .0349 0.0775 0.0776 0.0768 .0773

m-100 - 1 1.000 0.00 000 Qui ABC A05360 1600001? 1.310.000 140- 10 This Procedure use the protest the age of the track to Collect date from your method of chrobe and record them Collect at last 3 sport angle lower the angle by 1 degree Repeat the process until you get to 2 degrees the next page The Acceleration Time Angle: 7 What is the equation of the best-fit-line: Best-fit Equation y = (-0.536) +1.68t +(- 1.31) (Linear equation: y = (-1.08)t + 1.69) Therefore, what is the acceleration? y(x) =-0.536x2 +1.68x - 1.31 y(x) =- 1.072x + 1.68 Kinematics - 3 y(x) =- 1.072 The acceleration is -1.072 m/s2.