A dog running in an open field has components of velocity Vx = 3.4 m/s and Vy = -1.6 m/s at time t1 = 11.7 s. For the ti
Posted: Mon Jul 18, 2022 6:32 am
A dog running in an open field has components ofvelocity Vx = 3.4 m/s andVy = -1.6 m/s at time t1= 11.7 s.For the time interval from t1 = 11.7 s tot2 = 24.2 s, the average acceleration of thedog has magnitude 0.46 m/s2 and direction36.0° measured from the +x−axis towardthe +y−axis.A: At time t2 =24.2 s , what is the x-component of thedog's velocity?Vx = ? m/s
B: At time t2 =24.2 s , what is the y-component of the dog'svelocity?Vx = ? m/s
C: What is the magnitude of the dog'svelocity?V = ? m/s
D: What is the direction of the dog's velocity(measured from the +x−axis toward the +y−axis)?θ = ?°
B: At time t2 =24.2 s , what is the y-component of the dog'svelocity?Vx = ? m/s
C: What is the magnitude of the dog'svelocity?V = ? m/s
D: What is the direction of the dog's velocity(measured from the +x−axis toward the +y−axis)?θ = ?°