This is the question (b): This is an answer I found on answers: Shouldn't he divide t by 2? After all, I thought that the
Posted: Mon Jul 18, 2022 6:31 am
This is the question (b):
This is an answer I found on answers:
Shouldn't he divide t by 2? After all, I thought that the formula he used to discover t outputs the time it takes for the object to hit the floor, so shouldn't he divide by 2 since he is referring to the maximum altitude of the object (i.e. the vertex of the parabola)?
1. In recitation, you encountered a problem where a hiker was trying to throw her boot across a stream 12 meters wide. She accidentally threw it at an angle 65° above the horizontal when she meant to throw it at 35° above the horizontal. You may assume that she throws it from ground level. (a) At what speed would she need to throw the boot to get it across the stream when throwing it at 65° above the horizontal? (b) How high above the water would it travel in the process?
0 (Vc65) * time of tight (51)= 12 inst time of flighttr may T= 20 sin 65 } - height 10 V cos 65 * 2 * V sin6512 v² Sin (65x2) = 1269.8 V = 12.39m18 T= 2.298 ① Vsin 65 x T + Žg T² = H. = 2.29x 12 39 sin 65+ 9.8 x 2.292 = 51.41m
- This Is The Question B This Is An Answer I Found On Chegg Shouldn T He Divide T By 2 After All I Thought That The 1 (176.31 KiB) Viewed 43 times
- This Is The Question B This Is An Answer I Found On Chegg Shouldn T He Divide T By 2 After All I Thought That The 2 (343.64 KiB) Viewed 43 times
1. In recitation, you encountered a problem where a hiker was trying to throw her boot across a stream 12 meters wide. She accidentally threw it at an angle 65° above the horizontal when she meant to throw it at 35° above the horizontal. You may assume that she throws it from ground level. (a) At what speed would she need to throw the boot to get it across the stream when throwing it at 65° above the horizontal? (b) How high above the water would it travel in the process?
0 (Vc65) * time of tight (51)= 12 inst time of flighttr may T= 20 sin 65 } - height 10 V cos 65 * 2 * V sin6512 v² Sin (65x2) = 1269.8 V = 12.39m18 T= 2.298 ① Vsin 65 x T + Žg T² = H. = 2.29x 12 39 sin 65+ 9.8 x 2.292 = 51.41m