Answer Happy

Can you please help me solve this? I appreciate the time you’vetaken in advance.
(m /s) (m/s) (s) 5 10 15 20 3 4 5 6 7 (C) ol ? 3 4 B) Figure 1: 2. (al) In figure 1A: the average velocity between times: (i) Os to 2s is 5m/s to the right (ii)2s to ds is 2.5m/s to the left (iii) 4 to 5s is Om/s and (iv) 5s to 7s is 5m/s to the left (True, False) (2) In figure 1A: the average speed between times: (i) Os to 2s is 5m/s (ii)2s to 4s is 2.5m/s (ili) 4 to 5s is Om/s and (iv) 5s to 7s is 5m/s (True False) (13) In figure 1A: the average velocity between times: (i) Os to 4s is 1.25m/s to the right (11)0s to 5s is 1.0m/s to the right (iii) Os to 6s is 0 and (iv) Os to 7s is .714m/s to the left (True False) (14) In figure 1A: the average speed between times: (i) Os to 4s is 3.75m/s (ii)0 to 5s is 3.0m/s (111)Os to 6s is 3.333m/s and (iv) Os to 7is 3.57m/s (True False) (a5) In figure 1A : the Instantaneous velocity at a, 8, 7, and 6 are +5m/s, -2.5m/s, 0 and -5m/s respectively (True, False) (16) In figure 1A : the Instantaneous speed at a, 8. Y, and 8 are 5m/s, 2.5m/s, 0 and 5m/s respectively (True False) (61) In figure 1B : the total displacement between time Os and 4s is (4x2) + (4 X 1) + (2x1 + 2 x 1) = 11m (True False) (12) In figure 1B : the total distance travelled between time Os and 4s is (442) + |(4 x 1)| + (2x1 +2 x 1) = 11m (True False) (13) In figure 1B : the average acceleration between times: (1) Os to 2s is 2m/s2 to the right (ii)0s to 3s 1.33m/s2 to the right (iii)Os to 4s is 0.5m/s2 to the left (True False) (63) In figure 1B : the Instantaneous acceleration at 0, w and care +2m/s, Om/s2 and -2m/s2 respectively (True, False) In figure 1C: assume the particle starts at rest at t=0(Hint: p=w+ Av and Axe At: (cl) velocity at time (i) t = 10s is o + 10 x 2 = 20m/s, (ii)t = 158 is 20m/s + D and (iii)t = 158 is 20 + (5)(-3) = 5m/s (True False) (c2) the displacement between t = 0 to t = 20sec Ar = Axı + Ara + Ax3 = 20 10 + 20+205 + 5+20 5 = 262.5m (True False)