8) (3.) A force of 20 newtons stretches a spring 0.1 meters. A mass of 20 kilograms is attached to the end of the spring
Posted: Mon Jul 18, 2022 6:29 am
8) (3.) A force of 20 newtons stretches a spring 0.1 meters. A mass of 20 kilograms is attached to the end of the spring and the entire system is placed in a medium that offers a damping force that is numerically equal to 140 times the instantaneous velocity Set up an initial-value problem that models the spring-mass system if the mass is initially released from a point 0.25 meters below the equilibrium point with a upward velocity of 1 m/s. Then find the equation of motion.