Answer Happy

Two very large thin conducting plates with the same magnitude charge, but opposite sign, are held near each other. The plates are large enough and close enough together that fringing effects near the edges can be ignored (that is results of the Gauss' law for "Infinite" plate apply). The two plates are a distance D apart. The surface area of the face of each plate is A, the total charge on each plate is +Q and -Q, and the resulting uniform charge density is +00 and -00 so that 0oQ/A. Use the principle of superposition to identify the correct statement(s) about the electric field at points 1,2,3, and 4. The field at points 1 and 4 will be zero because the fields from positively and negatively plates will cancel each other The charge on positively charged plate will not contribute to the field at point 1 because there's metal between them The charge on negatively charged plate will not contribute to the field at point 4 because there's metal between them The fields at points 1 and 4 will be the same magnitude as from a single plate but in opposite directions The field at points 2 and 3 will be zero because the fields from negatively and positively charged plates cancel each other The field at points 2 and 3 will be the same and the magnitude of the field is twice that of the field from a single plate

Use your results from "Gauss' Law Plane" question in this pre-lab to and the answers to the previous question to calculate the electric field at points 1,2,3, and 4 in terms of go and Eo. Assume the positive direction if from right to left.