A disk of radius 2.27 m rotates about its axis. Points on the rim of the disk undergo tangential acceleration of magnitu
Posted: Mon Jul 18, 2022 5:53 am
A disk of radius 2.27 m rotates about its axis. Points on the rim of the disk undergo tangential acceleration of magnitude 2.17 m/s2. At a particular time, the rim has a tangential speed of 1.29 m/s. At a time 0.843 s later, what is the tangential speed v of a point on the rim, the magnitude of the point's radial acceleration Ar, and the magnitude of its total acceleration Otot? v= 2.36 m/s ar = 2.45 m/s2 atot = 3.28 m/s2