Answer Happy

Posted: **Sun Jul 17, 2022 7:58 pm**

: Q 2 000 An Object With A Small Amount Of Charge 9a 41 60 Nc Is At The Origin Of The Coordinate System Two Other Cha 1 (555.04 KiB) Viewed 37 times

: Q 2 000 An Object With A Small Amount Of Charge 9a 41 60 Nc Is At The Origin Of The Coordinate System Two Other Cha 2 (344.14 KiB) Viewed 37 times

: Q 2 000 An Object With A Small Amount Of Charge 9a 41 60 Nc Is At The Origin Of The Coordinate System Two Other Cha 3 (344.14 KiB) Viewed 37 times

: Q 2 000 An Object With A Small Amount Of Charge 9a 41 60 Nc Is At The Origin Of The Coordinate System Two Other Cha 4 (444.09 KiB) Viewed 37 times

: Q 2 000 An Object With A Small Amount Of Charge 9a 41 60 Nc Is At The Origin Of The Coordinate System Two Other Cha 5 (444.09 KiB) Viewed 37 times

: Q 2 000 An Object With A Small Amount Of Charge 9a 41 60 Nc Is At The Origin Of The Coordinate System Two Other Cha 6 (438.95 KiB) Viewed 37 times

: Q 2 000 An Object With A Small Amount Of Charge 9a 41 60 Nc Is At The Origin Of The Coordinate System Two Other Cha 7 (438.95 KiB) Viewed 37 times

Q -2.000 An object with a small amount of charge 9a = -41.60 nC is at the origin of the coordinate system. Two other charged particles are in the vicinity, as illustrated 9. = 43.44 .-12.60 m Particle b has 9 = +3.44 C (NOT nC) and is 12.60 m away from particle a. The line that connects a and b makes a 21.72° angle with the -- x axis. 4,- 41.60 nc Particle c has 4c = -2.00 C (NOT nC) and is 11.00 m away from particle a. The line that connects a and c makes a 58.88° angle with the --x axis. 1. Use this coordinate system to illustrate the forces happening to a due to the presence of qy and qc. • Draw only the two force vectors and label them Fab and Fac, accordingly. • Draw both vectors starting at the origin (tails at the origin). • You will come back later to adjust their lengths to better show their relative sizes.

2. Calculate the magnitude of vector Fab 3. Calculate the magnitude of vector Fac: 4. Go back to the illustration and adjust the size of the vectors to more accurately show whether one force is stronger that the other or if they are the same. 5. Calculate the x-component of each of the two forces. Use signs (+ for right; - for left) to designate their directions. Calculate Fabx here: Calculate Facx here:

6. Calculate the y-component of each of the two forces. Use signs (+ for up; - for down) to designate their directions. Calculate Faby here: Calculate Facy here: Page 2 of 3 7. Calculate the x and y-components of the resultant net force (net = Fab + ac). According to the signs of the components, in what quadrant is the resultant force vector?

8. Go back to the illustration in the first page and draw the resultant vector by completing the parallelogram formed by Fab and Fac. This has to confirm your answer about the quadrant of the resultant. 9. Here is an empty coordinate system. Illustrate the resultant force vector Free and draw its components. Calculate the angle that Fnet makes with respect to the +x axis. (Its unique address in the circle.) 10. Calculate the magnitude of the resultant force vector Free