Answer Happy

water Figure 3:

(c) The speed of the rocket at the edge of the cliff is wx = + 2a, Ar= 2(15) (21) = 25.1 m/s (True False) (d) It takes t = 4 ,- 25.11.-0 = 1.67s to reach the edge of the cliff: (True False) (e) While air borne the x and y displacement of the rocket are given by Ar = Wit = 25.1t and Ay = vivt + y2 = 0 + 4.912 = -4.942 ('True, False) (1) From the edge of the cliff it takes t ==3.03s for the rocket to hit the water (True False) (8) The horizontal range R follows from R = Axle-3.03. - 25.1(3.03) = 76.1m (True, False) (h) Since right before hitting the water the x and y component of the velocity of the rocket are uy = Wie = 25.1m/s and wy = 0 - 9.8(3.03) -29.69m/s the speed of the rocket is + = 25.1? + (-29.69)2 = 38.88m/s and the velocity vector makes an angle of =tan-1 949 49.70" clockwise with respect to + axis. (True False)

water Figure 3:

3. A rocket accelerates at 15m/s from rest for 21m on a frictionless horizontal surface (see figure 2.). The rocket stops firing at the cliff and falls freely no air resistance from height of 45m. (a) While on the frictionless surface the displacement and velocity of the rocket are Az = wzt + faz? = 0 + 152 = 7.5t2 and x = Vir + t = 0 + 150 = 15$ ('True, False) (b) While on the frictionless surface the following equations hold true Ar = L = t and ... = 3 + 2a,A= 0 + 2(15)(21) (True False) (c) The speed of the rocket at the edge of the cliff is wxl = +2a, Ar= 2(15) (21) = 25.1 m/s (True False) (d) It takes t = = 25.1.0 = 1.67s to reach the edge of the cliff: (True False) (e) While air borne the x and y displacement of the rocket are given by Ar = Wirt = 25.1t and Ay = y + Sal? = 0 + 4.942 = -4.922 (True False) (1) From the edge of the cliff it takes t v = -3.03s for the rocket to hit the water (8) The horizontal range R follows from R= Axl3.03. - 25.1(3.03) = 76.1m (True False) (True False) (h) Since right before hitting the water the x and y component of the velocity of the rocket are we = wis = 25.1 m/s and y = 0 - 9.8(3.03) = -29.69 m/s the speed of the rocket is v 2 + = 25.12 + (-29.69)2 = 38.88m/s and the velocity vector makes an angle of @ = tan-1 29.69 = 49.70° clockwise with respect to +x axis. (True False)