Answer Happy

12. + -19 points SerCP11 16.6.OP.041. My Notes Ask Your Teach The circuit in the figure below contains a 90.0 V battery and four capacitors. In the top parallel branch, there are two capacitors, one with a capacitance of C = 1.00 pF and another with a capacitance of 6.00 uF. In the bottom parallel branch, there are two more capacitors, one with a capacitance of 2.00 uF and another with a capacitance of C = 5.00 pF. 6.00 uF 2.00 uF 90.0 V (a) What is the equivalent capacitance (in pF) of the entire circuit? (b) What is the charge (in C) on each capacitor? on 1 on C2 on the 6.00 pF capacitor on the 2.00 pF capacitor > (c) What is the potential difference (in V) across each capacitor? across , across C2 across the 6.00 pF capacitor across the 2.00 pF capacitor > > >