Answer Happy

ON Normal text Times New 12 BIU A GD P 1 = ili E 314 Data And Results: Linear Mass density = 0.0048 g/cm Length of string between vibrator and pulley L=1.75 meters. Wavelength F Number of loops measured N Suspended Tension force Mass (kg) F Measured length LN for N loops L1 0.855 m L2|1.14 m 1 1 1.71 m 0.470 kg 0.230 kg 2 2.28 m 3 0.126 kg L31.28 m 2.56 m 4 L4 1.365 m 2.73 m 0.082 kg 0.057 kg 5 2.84 m L51.42 m L61.465 m 6 0.042 kg 2.93 m 7 0.032 kg L71.495 m 2.99 m 8 0.019 kg L81.51 m 3.02 m
1 match Begins with e vibrator and pulley L DATA TABLE Purpose: To determine the frequency of oscillation from normal modes. Number of loops measured N Suspended mass ( ) Tension force F* ( Measured length L for N loops Wavelength VE 1 Fi L 2 F 3 F 4 F. L, 5 F La 6 F 7 F L 8 L "For convenience, the tension weight force may be expressed in terms of (that is, if m=0.10 kg, then F - mg 0,10 N). Slope of graph Calculations (show work) Computed frequency Accepted frequency Percent error Don't forget units