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I just need help with Part C! P.S.: Units is ingrams/second for part C.
Hint for Part B:
Hint for Part C:
Ice 14 92 1289 55 V 0 13 22 w 922 Dr. Dean embeds the top resistor in a block of ice at 0°C. The latent heat of fusion for water is 334000 J/kg. EXAMPLE

Part Description Answer Chk History A. What is the equivalent resistance of A: 3.43 the three resistors that are in ohm parallel with each other? C: 3.434 (include units with answer) ohm # tries: 1 Show Details Hints: 0,0 What is the current through the top A: 0.229 A resistor? C: 0.2309 (include units with answer) # tries: 1 Show Details Hints: 1,1 0.74 g/s Format Check 16 pts. 96% The latent heat of fusion of water is a thermodynamic property that indicates how many Joules of Energy it takes to melt 1 kg of ice. The power in the top resistor (IPR) corresponds to the heat dissipated by that resistor, i.e. its energy available for melting the ice (1 W = 1 J/s). At what rate (mass/time) is the circuit melting the ice? (include units with answer) # tries: 2 Show Details OK - using first value as 0.740 g/s 2% try penalty Hints: 1,1

Hint #1: Only part of the current that goes through the battery goes through the top resistor. Intermediate Value Check Current through the battery: Check

Hint #1: Find power (1W = 1J/s) and relate power (in J/s) to latent heat of fusion (J/kg) Intermediate Value Check Power of top resistor (in ice): Check