Answer Happy

The full chemical equation for photosynthetic production of algae in seawater is: 106CO2​+16HNO3​+1H3​PO4​+122H2​O=⇒1C106​H263​O130​ N16​P+138O2​ where the compound C106​H263​O130​ N16​P (molec. mass 3870 g/ mole) represents the average atomic composition of algae. (Paytan and McLaughlin, The Ocean Phosphorous Cycle, Chem. Rev., 107, 563-576 (2007) 10.1021/cr0503613) On average, there is approximately 6.4×105 g of carbon (C) present in a square kilometer of ocean (Arteaga et al., Seasonal modulation of phytoplankton biomass in the Southern Ocean, Nature Communications, 11, Article number: 5364 (2020) 10.1038/s41467-020-19157-2). Q1 (5 pts). If all 6.4×105 g of carbon (C) is present as C106​H263​O130​ N16​P, how many moles of C106​H263​O130​ N16​P are contained in a square kilometer of ocean? Q2 (5 pts). How many moles of O2​ were produced in producing that C106​H263​O130​ N16​P ? Hint: This problem just looks complicated because C106​H263​O130​ N16​P seems like a complicated molecule. So, yeah, the numbers are big so you'll have to use a calculator. But this problem is nearly identical in terms of complexity to the Pivot hydrate lab you (should have) completed. The steps you want to follow are: