How many grams of oxygen gas (31.9988 g/mol) are required to completely combust 49.37g of methanol (32.0419 g/mol)? 2 CH
Posted: Fri Jul 15, 2022 5:01 pm
How many grams of oxygen gas (31.9988 g/mol) are required to completely combust 49.37g of methanol (32.0419 g/mol)?
2 CH3OH(g) + 3 02(8) > 2 CO2(g) + 4 H20(g)
2 CH3OH(g) + 3 02(8) > 2 CO2(g) + 4 H20(g)