Select all that true of the voltaic cell shown. C2t(aq)+Mg(5)⟶CU(5)+Mg2+(aq) The oxidation event occurring in the anode
Posted: Fri Jul 15, 2022 4:59 pm
What is true about the voltaic cell?
Select all that true of the voltaic cell shown. C2t(aq)+Mg(5)⟶CU(5)+Mg2+(aq) The oxidation event occurring in the anode is Mg(s)→M2+(aq)+2e− The reduction event occurring in the cathode is
The oxidation event occurring in the anode is Mg(s)→Mg2+(aq)+2e− The reduction event occurring in the cathode is Cu2++2e−→Cu(s) EMF in standard conditions is 2.696 V. Refer to your Standard Reduction Potential Table. When T=357 K,[Cu2+]=0.13M,[Mg2+]=0.10M,EMF=2.700 V. The formula is EMF=EMF∘−nFRTln([Cu2+][Mg2+] Where EMF=EMF in nonstandard conditions
When T=357 K,[Cu2+]=0.13M,[Mg2+]=0.10M,EMF=2.700 V. The formula is EMF∘=EMF∘−nFRTln([Cu2+][Mg2+] Where EMF = EMF in nonstandard conditions EMF∘=EMF in standard conditions R=8.314 J/(mol K) T= Kelvin temperature n= number of moles of electrons transferring from the anode to the c F=96485C/mol
Select all that true of the voltaic cell shown. C2t(aq)+Mg(5)⟶CU(5)+Mg2+(aq) The oxidation event occurring in the anode is Mg(s)→M2+(aq)+2e− The reduction event occurring in the cathode is
The oxidation event occurring in the anode is Mg(s)→Mg2+(aq)+2e− The reduction event occurring in the cathode is Cu2++2e−→Cu(s) EMF in standard conditions is 2.696 V. Refer to your Standard Reduction Potential Table. When T=357 K,[Cu2+]=0.13M,[Mg2+]=0.10M,EMF=2.700 V. The formula is EMF=EMF∘−nFRTln([Cu2+][Mg2+] Where EMF=EMF in nonstandard conditions
When T=357 K,[Cu2+]=0.13M,[Mg2+]=0.10M,EMF=2.700 V. The formula is EMF∘=EMF∘−nFRTln([Cu2+][Mg2+] Where EMF = EMF in nonstandard conditions EMF∘=EMF in standard conditions R=8.314 J/(mol K) T= Kelvin temperature n= number of moles of electrons transferring from the anode to the c F=96485C/mol