How many grams of Br2 are needed to form 69.3 g of AlBr3 ? 2Al(s)+3Br2(l)⟶2AlBr3( s) Step 1: Show the strategy for s
Posted: Fri Jul 15, 2022 4:59 pm
How many grams of Br2 are needed to form 69.3 g of AlBr3 ? 2Al(s)+3Br2(l)⟶2AlBr3( s) Step 1: Show the strategy for solving this problem.
Step 2: Show the conversions required to solve this problem and calculate the grams of Br2. 69.3 gAIBr3× x x =gBr2 grams of Br2 :
Step 2: Show the conversions required to solve this problem and calculate the grams of Br2. 69.3 gAIBr3× x x =gBr2 grams of Br2 :