Given the following thermochemical equations, 3Mg(s)+2NH3(g)→Mg3 N2(s)+3H2(g)ΔH∘=−371 kJ1/2 N2(g)+3/2H2(g)→NH3(g)
Posted: Fri Jul 15, 2022 4:45 pm
by answerhappygod
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Given the following thermochemical equations, 3Mg(s)+2NH3(g)→Mg3 N2(s)+3H2(g)ΔH∘=−371 kJ1/2 N2(g)+3/2H2(g)→NH3(g)ΔH∘=−46 kJ calculate ΔH∘ (in kilojoules) for the following reaction. 3Mg(s)+N2(8)→Mg3 N2(s)