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For a resction of the type A2(g)+B2(g)−2AB(g) with the rate law: −dtd[A2]=k[A2][B2] The value of the rate constant
Posted: Fri Jul 15, 2022 4:41 pm
by answerhappygod
- For A Resction Of The Type A2 G B2 G 2ab G With The Rate Law Dtd A2 K A2 B2 The Value Of The Rate Constant 1 (8.6 KiB) Viewed 49 times
For a resction of the type A2(g)+B2(g)−2AB(g) with the rate law: −dtd[A2]=k[A2][B2] The value of the rate constant at 302∘C is 2.45×10−4 L/mol s and at 50ag∘C the rate constant is 0.197U/mol s. The value of R is 8.3145 K. mol. Calculate the activatian energy for this reaction.