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Posted: **Fri Jul 15, 2022 4:41 pm**

: A Solution Was Prepared With 0 261 Mol Of Pyridinium Fluoride C5 H5 Nhf And Enough Water To Make A 1 00 L Pyridine 1 (16.68 KiB) Viewed 37 times

A solution was prepared with 0.261 mol of pyridinium fluoride (C5H5NHF) and enough water to make a 1.00 L. Pyridine ( C5H5 N) has a Kb=1.70×10−9 and HF has a Ka=6.30×10−4. Calculate the pH of the solution.

Answer Happy

A solution was prepared with 0.261 mol of pyridinium fluoride (C5​H5​NHF) and enough water to make a 1.00 L. Pyridine (

A solution was prepared with 0.261 mol of pyridinium fluoride (C5​H5​NHF) and enough water to make a 1.00 L. Pyridine (

A solution was prepared with 0.261 mol of pyridinium fluoride (C5H5NHF) and enough water to make a 1.00 L. Pyridine (

A solution was prepared with 0.261 mol of pyridinium fluoride (C5H5NHF) and enough water to make a 1.00 L. Pyridine (