Mark all correct statements (there might be more than one correct answer). The set S={XER:x2+x+1<0} is not bounded in R.
Posted: Tue Sep 07, 2021 7:51 am
Mark all correct statements (there might be more than one correct answer). The set S={XER:x2+x+1<0} is not bounded in R. Let A c R and a=sup (A), then -a=sup(-A), where -A={XER: -XEA}. | The set of rational numbers Q is an ordered field that is also complete. The real number 3 is not a rational number. The set S={XEQ:x2+x+1<0} does not he greatest lower bound in R.