Answer Happy

Question 2-1 The latent heat of fusion for water is 3.35×105 J/kg. Using this information, calculate the power of the immersion heater. Show your work and include units. G=L0∘×P×T Power of heater : Water vaporizathon =2.26×106 kg Specific heat H2​0=4186 Jlkg c′ Question 2-2: Etched into the handle of the immersion heater is the manufacturer's stated power output of the heater. According to your measurements, how accurate is the manufacture's stated power output? Calculate the percent difference. % diff = accepted ∣ accepted - measured ∣​×100 Discuss possible sources of error in your measurements that you used to calculate the power output of the heater.
- Record the total number of your heat pulses here: Total number of heat pulses : - From your graph, read off the following information: 24 Initial temperature of ice + water: 2.246c Final temperature of water : 0.5500 - Measure the mass of an empty Styrofoam cup and calculate the masses of the initial ice and water. Record your results here: 0.11Lg Mass of Styrofoam cup only : 0.00450k Mass of initial ice only :  Mass of initial water only : O. O34 3ke 0.14510 kg - 0.10560=0.0395 s - Sketch your graph in Graph 11-2.