PRL=ε2(RL+R)2RL I: to Plot a graph of PRL vs. RL and from the graph determine the value of RL at which the power
Posted: Thu Jul 14, 2022 8:06 pm
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15.5
E^2
23
1.3
E
231.040
825
15.2
70
231040
480
PRL=ε2(RL+R)2RL I: to Plot a graph of PRL vs. RL and from the graph determine the value of RL at which the power dissipated in RL is maximum. Pmax=mW at RL= ohm II: to Plot a graph of PRL vs. RL/(R+RL)2, then find the slope. - slope = - the slope represents = - the value of ε is 15.2v volt - Compare the measured the value of ε and the one obtained from the graph, and then find the percentage difference in your result