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Can you answer all questions!!
(i) (a) What is the equivalent capacitance (in μF ) of the entire circuit? x capacitances. μF (b) What is the charge (in μC ) on each capacitor? (c) What is the potential difference (in V) across each capacitor? across C2​ How is the capacitance related to the charge on the capacitor and the potential difference across the capacitor? V across the 6.00μF capacitor How is the capacitance related to the charge on the capacitor and the potential difference across the capacitor? V.
Use the worked example above to help you solve this problem. (i) (a) Determine the capacitance of the single capacitor that is equivalent to the parallel combination of capacitors shown in the figure above, if C1​=3.74μF,C2​=6.74μF,C3​=13.0μF,C4​=25.0μF, and V=18.8 V μF (b) Find the charge on the 13.0μF capacitor. x Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. μC (c) Find the total charge contained in the configuration. - μC EXERCISE HINTS: GETTING STARTED I I'M STUCK! Use the values from PRACTICE IT to help you work this exercise. Find the charge on C4​. Q= μC
Use the worked example above to help you solve this problem. Four capacitors are connected in series with a battery, as in the figure below, where C1​=3.30μF1​C2​=6.44μF1​C3​=12.2μF1​C4​=25.0μF, V=18.3 V (a) Calculate the capacitance of the equivalent capacitor. μF (b) Compute the charge on C3​. μC (c) Find the voltage drop across C3​. V EXERCISE HINTS: GETTING STARTED I I'M STUCK! Use the values from PRACTICE IT to help you work this exercise. C4​ is removed from the circuit, leaving only three capacitors in series. (a) Find the equivalent capacitance. Ceq ​= -र्ष You are on the right track, but you have made an algebraic mistake. Checking the units might help you find where you went wrong. μF (b) Find the charge on C2​. Q= x You are correct, Qeq​=Ceq​V, but your value of Ceq​ was incorrect. μC (c) Find the voltage drop across C2​. ΔV=