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p(x∣ω1)=θ12x+2exp[−2θ12(x+2)2],θ1>0 p(x∣ω2)=2πσ21exp[−21(σ2x−μ2)2]
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p(x∣ω1)=θ12x+2exp[−2θ12(x+2)2],θ1>0 p(x∣ω2)=2πσ21exp[−21(σ2x−μ2)2]
Posted:
Thu Jul 14, 2022 4:51 pm
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answerhappygod
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p(x∣ω1)=θ12x+2exp[−2θ12(x+2)2],θ1>0 p(x∣ω2)=2πσ21exp[−21(σ2x−μ2)2]