Step 2 To determine the critical numbers of g(x), set g′(x) equal to zero and solve for x. g′(x)2x−42x=0=0=0=2 2(x−2∼2
Posted: Thu Jul 14, 2022 4:47 pm
Step 2 To determine the critical numbers of g(x), set g′(x) equal to zero and solve for x. g′(x)2x−42x=0=0=0=2 2(x−2∼2)=0 Step 3 First consider the interval (−∞,2). Let x=0. g′(x)=2(x−2) g′(0)=2(0−2) g′(0)=2(−2) g′(0)=−4 Step 4 Since g′(0)<0, for which interval is the function decreasing. (Enter your answer using interval notation.)