Solution using Method of Variation of Parameters
Posted: Thu Jul 14, 2022 4:43 pm
Solution using Method of Variation of Parameters
y′′+2y′+y=15e−xx+1 ANs y=e−x[C0+C1x+4(x+1)25]
- Solution Using Method Of Variation Of Parameters 1 (9.28 KiB) Viewed 42 times