Consider the function F(x)=∫0xe−2t2dt. Express F(x) as a power series in x. (hint: ex=n=1∑∞n!xn) ∑n=0∞(2n+1)n!(−1)n2
Posted: Thu Jul 14, 2022 4:43 pm
Consider the function F(x)=∫0xe−2t2dt. Express F(x) as a power series in x. (hint: ex=n=1∑∞n!xn) ∑n=0∞(2n+1)n!(−1)n2nx2n∑n=0∞(2n+1)n!(−1)n2nx2n+1∑n=0∞(2n+1)n!(−1)nx2n+1∑n=0∞(2n+1)n!(−1)nxn