0.05x2 dollars. So, the cost of manufacturing x vests in one given day is given by C(x)=0.05x2+15x+500, where 0
Posted: Thu Jul 14, 2022 4:42 pm
0.05x2 dollars. So, the cost of manufacturing x vests in one given day is given by C(x)=0.05x2+15x+500, where 0<x<150. (A) What is the average cost Cˉ(x) per vest if x vests are produced in one day? (B) Find the critical numbers of Cˉ(x), the intervals on which the average cost per vest is decreasing, the intervals on which the average cost per vest is increasing, and the local extrema. Do not graph. (A) Cˉ(x)=
Posted: Thu Jul 14, 2022 4:42 pm
0.05x2 dollars. So, the cost of manufacturing x vests in one given day is given by C(x)=0.05x2+15x+500, where 0<x<150. (A) What is the average cost Cˉ(x) per vest if x vests are produced in one day? (B) Find the critical numbers of Cˉ(x), the intervals on which the average cost per vest is decreasing, the intervals on which the average cost per vest is increasing, and the local extrema. Do not graph. (A) Cˉ(x)=