Answer Happy

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x)=e−3x,[0,1] No, f is not continuous on [0,1]. There is not enough information to verify if this function satisfies the Mean Value Theorem. Yes, f is continuous and differentiable on R, so it is continuous on [0,1] and differentiable on (0,1). Yes, it does not matter if f is continuous or differentiable; every function satisfies the Mean Value Theorem. No, f is continuous on [0,1] but not differentiable on (0,1). If it satisfies the hypotheses, find all numbers c that satisfy the conclusion of the Mean Value Theorem. (Enter your answers as a comma-separated list. If it does not satisfy the hypotheses, enter DNE). c=