Answer Happy • H∗+ZV=0 f2+2(t−1)e2+(t−2)×w(0) w2+=−9 62+2y=0

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H∗+ZV=0 f2+2(t−1)e2+(t−2)×w(0) w2+=−9 62+2y=0

Posted: Thu Jul 14, 2022 4:37 pm

by answerhappygod

: H Zv 0 F2 2 T 1 E2 T 2 W 0 W2 9 62 2y 0 1 (8.3 KiB) Viewed 36 times

: H Zv 0 F2 2 T 1 E2 T 2 W 0 W2 9 62 2y 0 2 (9.33 KiB) Viewed 36 times

: H Zv 0 F2 2 T 1 E2 T 2 W 0 W2 9 62 2y 0 3 (9.33 KiB) Viewed 36 times

H∗+ZV=0 f2+2(t−1)e2+(t−2)×w(0) w2+=−9
62+2y=0