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The magnitude of the electrostatic force between two point charges Q and q of the same sign is given by F(x)=x2kQq, whe
Posted: Thu Jul 14, 2022 4:35 pm
by answerhappygod
- The Magnitude Of The Electrostatic Force Between Two Point Charges Q And Q Of The Same Sign Is Given By F X X2kqq Whe 1 (320.16 KiB) Viewed 14 times
- The Magnitude Of The Electrostatic Force Between Two Point Charges Q And Q Of The Same Sign Is Given By F X X2kqq Whe 2 (212.38 KiB) Viewed 14 times
The magnitude of the electrostatic force between two point charges Q and q of the same sign is given by F(x)=x2kQq, where x is the distance between the charges and k=9×109 N⋅m2/C2 is a physical constant (C stands for coulomb, the unit of charge; N stands for newton, the unit of force). Use this information to answer parts (a) through (c) below. A. F′(x)=−x31.8×10yQq N/m B. F′(x)=−x32QqN/m F′(x)=−x31.8×1010QqN/m D. F′(x)=−x21.8×1010QqN/m b. For two identical charges with Q=q=1C, what is the instantaneous rate of change of the force at a separation of x=0.003 m ? N/m (Type your answer in scientific notation, using the appropriate symbol from the math palette for any multiplication. Simplify your answer. Round to two decimal places as needed.)
Use the table to the right to find the given derivative. dxd[xf(x)]∣∣x=5 dxd[xf(x)]∣∣x=5= (Simplify your answer. )