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f(x)=8xcos(31x2) n=0∑∞3n((2n)!)(−1)n8x4n+1
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f(x)=8xcos(31x2) n=0∑∞3n((2n)!)(−1)n8x4n+1
Posted:
Thu Jul 14, 2022 4:34 pm
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answerhappygod
F X 8xcos 31 X2 N 0 3n 2n 1 N8x4n 1 1 (89.91 KiB) Viewed 17 times
f(x)=8xcos(31x2) n=0∑∞3n((2n)!)(−1)n8x4n+1